-8x^2+74x-18=0

Solution for -8x^2+74x-18=0 equation:

-8x^2+74x-18=0

a = -8; b = 74; c = -18;
Δ = b2-4ac
Δ = 742-4·(-8)·(-18)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-70}{2*-8}=\frac{-144}{-16}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+70}{2*-8}=\frac{-4}{-16}
=1/4
$